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4x^2-3x-430=0
a = 4; b = -3; c = -430;
Δ = b2-4ac
Δ = -32-4·4·(-430)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-83}{2*4}=\frac{-80}{8} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+83}{2*4}=\frac{86}{8} =10+3/4 $
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